The equation of the normal to the curve y = –√x + 2 at the point of its intersection with the bisector of the first quadrant is :
(A) 2x – y + 1 = 0
(B) 4x – y + 16 = 0
(C) 4x – y = 16
(D) 2x – y – 1 = 0
Home Modern › Forums › UPSEE › The equation of the normal to the curve y = –√x + 2 at the point of its intersection with the bisector of the first quadrant is : (A) 2x – y + 1 = 0(B) 4x – y + 16 = 0 (C) 4x – y = 16 (D) 2x – y – 1 = 0 › Reply To: The equation of the normal to the curve y = –√x + 2 at the point of its intersection with the bisector of the first quadrant is : (A) 2x – y + 1 = 0(B) 4x – y + 16 = 0 (C) 4x – y = 16 (D) 2x – y – 1 = 0
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