The point on the line 4x + 3y = 5, which is equidistant from (1, 2) and (3, 4), is
(a) (7,-4)
(b) (-10,15)
(c) (1/7, 8/7)
(d) (0, 5/4)
Home Modern › Forums › UPSEE › The point on the line 4x + 3y = 5, which is equidistant from (1, 2) and (3, 4), is(a) (7,-4) (b) (-10,15)(c) (1/7, 8/7)(d) (0, 5/4) › Reply To: The point on the line 4x + 3y = 5, which is equidistant from (1, 2) and (3, 4), is(a) (7,-4) (b) (-10,15)(c) (1/7, 8/7)(d) (0, 5/4)
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