Reply To:

The Boolean theorem AB + A’C + BC = AB + A’C corresponds to
(A) (A + B) ∙ (A’ + C) ∙ (B + C) = (A + B) ∙ (A’ + C)
(B) AB + A’C + BC = AB + BC

(C) AB + A’C + BC = (A + B) ∙ ( A ‘+ C) ∙ (B + C)
(D) (A + B) ∙ (A’ + C) ∙ (B + C) = AB + A’C

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The Boolean theorem AB + A’C + BC = AB + A’C corresponds to
(A) (A + B) ∙ (A’ + C) ∙ (B + C) = (A + B) ∙ (A’ + C)
(B) AB + A’C + BC = AB + BC

(C) AB + A’C + BC = (A + B) ∙ ( A ‘+ C) ∙ (B + C)
(D) (A + B) ∙ (A’ + C) ∙ (B + C) = AB + A’C

› Reply To:

The Boolean theorem AB + A’C + BC = AB + A’C corresponds to
(A) (A + B) ∙ (A’ + C) ∙ (B + C) = (A + B) ∙ (A’ + C)
(B) AB + A’C + BC = AB + BC

(C) AB + A’C + BC = (A + B) ∙ ( A ‘+ C) ∙ (B + C)
(D) (A + B) ∙ (A’ + C) ∙ (B + C) = AB + A’C