Reply To:

If the mean of a normal frequency distribution of 1000 items is 25 and its standard deviation is 2.5, then its maximum ordinate is
(A) (1000/√2π).e^{-25
(B) 1000/√2π
(C) (1000/√2π ).e_-2.5}
(D) 400/√2π

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If the mean of a normal frequency distribution of 1000 items is 25 and its standard deviation is 2.5, then its maximum ordinate is
(A) (1000/√2π).e^{-25
(B) 1000/√2π
(C) (1000/√2π ).e_-2.5}
(D) 400/√2π

› Reply To:

If the mean of a normal frequency distribution of 1000 items is 25 and its standard deviation is 2.5, then its maximum ordinate is
(A) (1000/√2π).e^{-25
(B) 1000/√2π
(C) (1000/√2π ).e_-2.5}
(D) 400/√2π