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Consider the following statements

#define hypotenuse (a, b) sqrt (a*a+b*b); 

The macro call hypotenuse(a+2,b+3);
(A) Finds the hypotenuse of a triangle with sides a+2 and b+3
(B) Finds the square root of (a+2)² and (b+3)²
(C) Is invalid
(D) Find the square root of 3*a + 4*b + 5

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Consider the following statements

#define hypotenuse (a, b) sqrt (a*a+b*b); 

The macro call hypotenuse(a+2,b+3);
(A) Finds the hypotenuse of a triangle with sides a+2 and b+3
(B) Finds the square root of (a+2)² and (b+3)²
(C) Is invalid
(D) Find the square root of 3*a + 4*b + 5

› Reply To:

Consider the following statements

#define hypotenuse (a, b) sqrt (a*a+b*b); 

The macro call hypotenuse(a+2,b+3);
(A) Finds the hypotenuse of a triangle with sides a+2 and b+3
(B) Finds the square root of (a+2)² and (b+3)²
(C) Is invalid
(D) Find the square root of 3*a + 4*b + 5