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Reply To:
If vectors $\vec{a}=2\hat{i}+\lambda \hat{j}+\hat{k }$ and $\vec{b}=\hat{i}-2 \hat{j}+3\hat{k }$ are perpendicular to each other, then value of λ is
(A) 2/5
(B) 2
(C) 3
(D) 5/2

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If vectors $\vec{a}=2\hat{i}+\lambda \hat{j}+\hat{k }$ and $\vec{b}=\hat{i}-2 \hat{j}+3\hat{k }$ are perpendicular to each other, then value of λ is
(A) 2/5
(B) 2
(C) 3
(D) 5/2
Reply To:
If vectors $\vec{a}=2\hat{i}+\lambda \hat{j}+\hat{k }$ and $\vec{b}=\hat{i}-2 \hat{j}+3\hat{k }$ are perpendicular to each other, then value of λ is
(A) 2/5
(B) 2
(C) 3
(D) 5/2

Updated on September 25, 2023

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If vectors $\vec{a}=2\hat{i}+\lambda \hat{j}+\hat{k }$ and $\vec{b}=\hat{i}-2 \hat{j}+3\hat{k }$ are perpendicular to each other, then value of λ is

(A) 2/5
(B) 2
(C) 3
(D) 5/2

› Reply To:

If vectors $\vec{a}=2\hat{i}+\lambda \hat{j}+\hat{k }$ and $\vec{b}=\hat{i}-2 \hat{j}+3\hat{k }$ are perpendicular to each other, then value of λ is

(A) 2/5
(B) 2
(C) 3
(D) 5/2

Anonymous

Guest

September 25, 2023 at 5:06 am

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