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What is the output of the following ‘c’ code assuming it runs on a byte addressed little endian machine?

#include <stdio.h> int main( ) { int x; char *ptr; x = 622,100,101; printf("%d", (*(char *)&x) * (x % 3)); return 0; }

(A) 622
(B) 311
(C) 22
(D) 110

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