If the line x + 2ky + 3 = 0 is a diameter of the circle x2 + y2 – 6x + 2y = 0, then k is equal to
(a) 3
(b) -5
(c) -1
(d) 5
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If the line x + 2ky + 3 = 0 is a diameter of the circle x2 + y2 – 6x + 2y = 0, then k is equal to
(a) 3
(b) -5
(c) -1
(d) 5
Viewing 1 replies (of 1 total)
Viewing 1 replies (of 1 total)