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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 7301. |
X_2 is a greenish yellow gas with an offensive smell used in water purification. It partially dissolves in water to give a solution which turns blue litmus red. When X_2 is passed through NaBr solution, Br_2 is obtained. Write general electronic configuration of this group. |
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Answer» Solution :`X_2` is chlorine which is a yellowish green GAS. It DISSOLVES in water forming HCl and HCLO `Cl_2+ H_2O to HCl + HClO` HCl TURNS blue litmus to red . `Cl_2 + 2NaBr to 2NaCl + Br_2` Electronic configuration `NS^(2) np^(7)`. |
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| 7302. |
X_2 is a greenish yellow gas with an offensive smell used in water purification. It partially dissolves in water to give a solution which turns blue litmus red. When X_2 is passed through NaBr solution, Br_2 is obtained. What are the products obtained when X_2 reacts with H_2O ? Write chemical equations. |
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Answer» SOLUTION :`X_2` is chlorine which is a yellowish GREEN GAS. It DISSOLVES in water forming HCl and HClO `Cl_2+ H_2O to HCl + HClO` HCl turns blue litmus to RED . `Cl_2 + 2NaBr to 2NaCl + Br_2` `Cl_2 + H_2O to HCl + HClO` |
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| 7303. |
X_2 is a greenish yellow gas with an offensive smell used in water purification. It partially dissolves in water to give a solution which turns blue litmus red. When X_2 is passed through NaBr solution, Br_2 is obtained. What happens when X_2 reacts with hot and conc. NaOH ? Give equations. |
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Answer» Solution :`X_2` is chlorine which is a yellowish green gas. It dissolves in water forming HCl and HCLO `Cl_2+ H_2O to HCl + HClO` HCl turns BLUE LITMUS to RED . `Cl_2 + 2NaBr to 2NaCl + Br_2` `3Cl_2 + 6NaOH ( " hot and CONC.") to 5NaCl + NaClO_3 + 3H_2O` |
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| 7304. |
What is Werner’s coordination theory ? |
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Answer» Solution :A metal ion in a complex has TWO types of valencies known as PRIMARY and SECONDARY valency. Primary valency of the metal ion is satisfied by ANIONS and ligands. Secondary valency of the metal ion is satisfied by ligands only. |
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| 7305. |
When degenerate d-orbitals of an isolated atom/ion come under influence of magnetic field of ligands, the degeneray is lost. The two set t_(2g)(d_(xy),d_(yz),d_(xz)) and e_(g) (d_(x^(2))-d_(x^(2)-y^(2)) are either stabilized or destabilized depending upon the nature of magnetic field. it can be expressed diagrammatically as: Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for tetrahedral complexes, Delta is about 4/9 times to Delta_(0) (CFSE for octahedral complex). this energy lies in visible region and i.e., why electronic transition are responsible for colour. such transition are not possible with d^(0) and d^(10) configuration. Q. The vlaue of CFSE (Delta_(0)) for completes given below follow the order, (I) [Co(NH_(3))_(6)]^(3+) (II) [Rh(NH_(3))_(6)]^(3+) (III) [IR(NH_(3))_(6)]^(3+) |
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Answer» `I LT II lt III` |
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| 7306. |
When copper is heated with cone.HNO_(3)It produces : |
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Answer» `CU(NO_(3))_(2), NO and NO_(2)` |
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| 7307. |
Which of the following are arranged in the decreasing order of dipole moment? |
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Answer» `CH_(3)F,CH_(3)Cl,CH_(3)Br` |
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| 7308. |
The standard Gibbs free energy change DeltaG^(@) is related to equilibrium constant K_(p) as |
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Answer» <P>`K_(p)=-RTlnDeltaG^(@)` |
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| 7309. |
X_2 is a greenish yellow gas with an offensive smell used in water purification. It partially dissolves in water to give a solution which turns blue litmus red. When X_2 is passed through NaBr solution, Br_2 is obtained. Identify X_2. |
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Answer» SOLUTION :`X_2` is chlorine which is a YELLOWISH green gas. It DISSOLVES in WATER forming HCl and HClO `Cl_2+ H_2O to HCl + HClO` HCl turns blue litmus to red . `Cl_2 + 2NaBr to 2NaCl + Br_2` `X_2` is chlorine |
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| 7310. |
X_2 is a greenish yellow gas with an offensive smell used in water purification. It partially dissolves in water to give a solution which turns blue litmus red. When X_2 is passed through NaBr solution, Br_2 is obtained. Name the group to which it belongs. |
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Answer» SOLUTION :`X_2` is chlorine which is a yellowish green gas. It dissolves in water forming HCL and HClO `Cl_2+ H_2O to HCl + HClO` HCl turns blue LITMUS to RED . `Cl_2 + 2NaBr to 2NaCl + Br_2` It belongs to group 17. |
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| 7311. |
The same amount of electricity was passed through two separate electrolytic cells containing solutions of nickel nitrate and chromium nitrate respectively . If 0.3 g of nickel was deposited in the first cellthe amount of chromium deposited is (at .mass Ni = 59 , Cr = 52) |
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Answer» `0.1` g `(0.3)/(59//2) = (W)/(52//3)` `W_(Cr) = 0.176` g |
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| 7312. |
Types of bonding in solid carbon dioxide are : |
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Answer» Hydrogen bonding |
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| 7313. |
Which one of the following pairs represents linkage isomers? |
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Answer» `[Cu(NH_(3))_(4)][PtCl_(4)]` and `[PT(NH_(3))_(4)[CuCl_(4)]` |
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| 7314. |
Which one of the following is used as cathode in Mercury button cell ? |
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Answer» ZINC |
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| 7315. |
Which of the following facts about the complex [Cr(NH_(3))_(6)]Cl_(3) is wrong ? |
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Answer» The complexis an outer orbital complex |
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| 7316. |
Total number of mono chlorinated compounds are possible for cumene (including stereo isomers) |
Answer» 
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| 7317. |
Which of the following option is correct with respect to True/False nature of statements. Statement-1: Experimental determination of Osmotic pressure is easiest as compared to other colligative properties. Statement-2: Henry's constant of a gas is directly dependent on pressure. Statement-3: The exent of adsorption increases with increase of surface area per unit mass of the adsorbent at given temperature and pressure. ltbr. Statement -4:H_(2)O which is diamagneitc substance when kept in a magnetic field will experience no interactions. |
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Answer» All STATEMENTS are CORRECT |
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| 7318. |
What is PHBV ? How it is synthesized ? What are its uses ? |
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Answer» Solution :PHBV STANDS for poly-`beta`-hydroxy butyrate co`beta`-hydroxy valenrate. It is synthesised by the polymerisation of `beta`-hydroxybutyric acid and `beta`- hydrovaleric acid. `nHO-UNDERSET(R)underset(|)CH-CH_2 - COOH to (-O-underset(R)underset(|)CH-CH_2 - underset(O)underset(||)C-O-)_n` Where R= `-CH_3 ` or `-C_2 H_5` Uses. It is used in orthopaedic devices and in controlled DRUG release. |
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| 7319. |
Which of the following are the main source of carbohydrates |
| Answer» Answer :A | |
| 7320. |
which of the following can be used as laboratory method to differentiated glucose form fructose ? |
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Answer» `Br_(2)+H_(2)O` |
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| 7321. |
Write the reaction of (i) aromatic and (ii) aliphatic primary amines with nitrous acid. |
Answer» Solution :Aromatic primary amines REACTS with `HNO_(2)` at 273-278 K to form aromatic DIAZONIUM salts.  Aliphatic primary amines also react with `HNO_(2)` at 273-278 K to form aliphatic diazonium salts. But these are unstable even at this low TEMPERATURE and thus decompose readily to form a MIXTURE of compounds consisting of alkyl chlorides, alkenes and ALCOHOLS, out of this alcohols generally predominate. `underset("Ethylamine")(CH_(3)CH_(2)NH_(2))+HNO_(2)+HCl underset((-2H_(2)O))overset(273-278K)to underset("Ethanediazonium chloride (unstable)")([CH_(3)CH_(2)-overset(+)(N)-=N]Cl^(-)) overset(H_(2)O)to underset("Ethanol")(CH_(3)CH_(2)OH)+N_(2)+HCl` |
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| 7322. |
Which one of the following bases is not present in DNA ? |
| Answer» Solution :Quinoline | |
| 7323. |
Which of the following is an elastomer ? |
| Answer» Solution :All of these | |
| 7324. |
What is the coordination number of metal in the complex ion [Fe(C_(2)O_( 4))_(3)]^(3-) ? |
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Answer» 2 |
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| 7325. |
Which of the following does not involve coagulation? |
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Answer» peptisation |
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| 7326. |
The size of the collodial particles lies in the range……….nm. |
| Answer» SOLUTION :`1-1000` | |
| 7327. |
Which of the following does not give iodoform reaction? CH_(3)-CH_(2)OH, CH_(3)-underset(OH)underset(|)(CH) -CH_(2)-CH_(3), CH_(3)-underset(OH)underset(|)(CH)-CH_(3), CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-OH |
| Answer» Solution :`CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)C-OH` Tertiary BUTYL ALCOHOL does not GIVE iodoform reaction. All other compounds CONTAIN a H atoms and they undergo iodoform reaction. | |
| 7328. |
Which of the following compound is used for preparation of melamine formaldehyde polymer |
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Answer»
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| 7329. |
Which of the following is true with regards to nucleosides |
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Answer» Nucleoside is formed from nitrogen BASE + SUGAR |
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| 7330. |
Whichof the followingcan formananhydride on heating? |
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Answer»
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| 7331. |
When degenerate d-orbitals of an isolated atom/ion come under influence of magnetic field of ligands, the degeneray is lost. The two set t_(2g)(d_(xy),d_(yz),d_(xz)) and e_(g) (d_(x^(2))-d_(x^(2)-y^(2)) are either stabilized or destabilized depending upon the nature of magnetic field. it can be expressed diagrammatically as: Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for tetrahedral complexes, Delta is about 4/9 times to Delta_(0) (CFSE for octahedral complex). this energy lies in visible region and i.e., why electronic transition are responsible for colour. such transition are not possible with d^(0) and d^(10) configuration. Q. Cr^(3+) form four complexes with four different ligands which are [Cr(Cl)_(6)]^(3-), [Cr(H_(2)O)_(6)]^(3+), [Cr(NH_(3))_(6)]^(3+) and [Cr(CN)_(6)]^(3-), the order of CFSE (Delta_(0)) in these complexes in the order: |
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Answer» `[CrCl_(6)]^(3+) and [Cr(CN)_(6)]^(3+)=[Cr(NH_(3))_(6)]^(3+)=[Cr(CN)_(6)]^(3-)` |
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| 7332. |
Which of the following can be used to prepare propene and also propane in single step? |
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Answer» `C_(2)H_(5)CO Cl` 
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| 7333. |
When degenerate d-orbitals of an isolated atom/ion come under influence of magnetic field of ligands, the degeneray is lost. The two set t_(2g)(d_(xy),d_(yz),d_(xz)) and e_(g) (d_(x^(2))-d_(x^(2)-y^(2)) are either stabilized or destabilized depending upon the nature of magnetic field. it can be expressed diagrammatically as: Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for tetrahedral complexes, Delta is about 4/9 times to Delta_(0) (CFSE for octahedral complex). this energy lies in visible region and i.e., why electronic transition are responsible for colour. such transition are not possible with d^(0) and d^(10) configuration. Q. The d-orbitals, which are stabillized in an octahedral magnetic field, are: |
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Answer» `d_(XY) and d_(X^(2))` |
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| 7334. |
When degenerate d-orbitals of an isolated atom/ion come under influence of magnetic field of ligands, the degeneray is lost. The two set t_(2g)(d_(xy),d_(yz),d_(xz)) and e_(g) (d_(x^(2))-d_(x^(2)-y^(2)) are either stabilized or destabilized depending upon the nature of magnetic field. it can be expressed diagrammatically as: Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for tetrahedral complexes, Delta is about 4/9 times to Delta_(0) (CFSE for octahedral complex). this energy lies in visible region and i.e., why electronic transition are responsible for colour. such transition are not possible with d^(0) and d^(10) configuration. Q. Ti^(3+)(aq). is purple while Ti^(4+)(aq). is colourless because: |
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Answer» there is not crystal FIELD effecin `Ti^(4+)` |
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| 7335. |
When degenerate d-orbitals of an isolated atom/ion come under influence of magnetic field of ligands, the degeneray is lost. The two set t_(2g)(d_(xy),d_(yz),d_(xz)) and e_(g) (d_(x^(2))-d_(x^(2)-y^(2)) are either stabilized or destabilized depending upon the nature of magnetic field. it can be expressed diagrammatically as: Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for tetrahedral complexes, Delta is about 4/9 times to Delta_(0) (CFSE for octahedral complex). this energy lies in visible region and i.e., why electronic transition are responsible for colour. such transition are not possible with d^(0) and d^(10) configuration. Q. For an octahedral complex, which of the followin d-electron configuration will give maximum CFSE? |
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Answer» HIGH SPIN `d^(6)` |
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| 7336. |
When degenerate d-orbitals of an isolated atom/ion come under influence of magnetic field of ligands, the degeneray is lost. The two set t_(2g)(d_(xy),d_(yz),d_(xz)) and e_(g) (d_(x^(2))-d_(x^(2)-y^(2)) are either stabilized or destabilized depending upon the nature of magnetic field. it can be expressed diagrammatically as: Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for tetrahedral complexes, Delta is about 4/9 times to Delta_(0) (CFSE for octahedral complex). this energy lies in visible region and i.e., why electronic transition are responsible for colour. such transition are not possible with d^(0) and d^(10) configuration. Q. Which of the following is correct arrangement of ligand in terms of the Dq values of their complexes with any particularr 'hard' metal ion: |
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Answer» `CL^(-) lt F^(-) lt NCS^(-) lt NH_(3) lt CN^(-)` |
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| 7337. |
Which of the following mixture is used as promoters in production of ammonia gas by Haber's process ? |
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Answer» `Zn + Al_(2)O_(3)` |
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| 7338. |
The treatment of CH_3underset(CH_3)underset(|)C=CH_2 with NalO_4 or boiling KMnO_4 produces |
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Answer» `CH_3COCH_3+CH_2O` |
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| 7339. |
When degenerate d-orbitals of an isolated atom/ion come under influence of magnetic field of ligands, the degeneray is lost. The two set t_(2g)(d_(xy),d_(yz),d_(xz)) and e_(g) (d_(x^(2))-d_(x^(2)-y^(2)) are either stabilized or destabilized depending upon the nature of magnetic field. it can be expressed diagrammatically as: Value of CFSE depends upon nature of ligand and a spectrochemical series has been made experimentally, for tetrahedral complexes, Delta is about 4/9 times to Delta_(0) (CFSE for octahedral complex). this energy lies in visible region and i.e., why electronic transition are responsible for colour. such transition are not possible with d^(0) and d^(10) configuration. Q. The extent of crystal field splitting in octahedral complexes of the given metal with particular weak field ligand are: |
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Answer» `Fe(III) lt Cr(III) lt RH(III) lt Ir(III)` |
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| 7340. |
Which of the following will form a reversible sol? |
| Answer» Answer :A | |
| 7341. |
Which of the following reagents would distinguish ciscyclopenta 1,2-diolfrom the trans-isomer |
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Answer» Acetone |
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| 7342. |
Which of the following is not a characteristics of a crystalline solid? |
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Answer» Definite heat of fusion |
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| 7343. |
Which one of the following is an example of an antipyretic? |
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Answer» ACETYL SALICYLIC ACID |
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| 7344. |
When electricity is passed through molten AlCl_3, 13.5 g. of Al is deposited. The number ofFaradays must be |
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Answer» `0.5` |
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| 7345. |
Which of the metals cannot be obtained by the process of leaching? |
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Answer» Aluminium |
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| 7346. |
We have taken a saturated solution of AgBr.K_(sp) of AgBr is 12xx10^(-14).If 10^-7 mole of AgNO_3 are added to 1 litre of this solution find conductivity (specific conductance) of this solution in terms of 10^-7Sm^-1"mole"^-1. [Given ,lambda_(Ag^+)^0=6xx10^-3Sm^2mol^-1, lambda_(Br^-)^0=8xx10^-3Sm^2mol^-1, lambda_(NO_3^-)^0=7xx10^-2Sm^2mol^-1 |
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Answer» |
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| 7347. |
Write IUPAC name of CH_(3)-underset(OH)underset(|)(CH)-CH_(2)-COOH |
| Answer» SOLUTION :3-Hydroxybutanoic ACID /3-hydroxybutan-1-oic acid. | |
| 7348. |
When copper is heated with conc HNO_(3) it produces ………… . |
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Answer» `CU(NO_(3))_(2), NO and NO_(2)` |
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| 7349. |
To obtain steel entirely free from sulphur and phosphorus, the process used is |
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Answer» Electrothermal process |
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| 7350. |
Which one of the following complexes shows optical isomerism? |
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Answer» `[Co(NH_(3))_(4)Cl_(2)]CL` |
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