Explanation:The balanced equation is  2 CH 3 OH + 3 O 2 → 2 CO 2 + 4 H 2 O Explanation: You follow a systematic procedure to BALANCE the equation. Start with the unbalanced equation: CH 3 OH + O 2 → CO 2 + H 2 O A method that often works is first to balance everything other than  O and  H , then balance  O , and finally balance  H . Another useful procedure is to start with what looks like the most COMPLICATED formula. The most complicated formula looks like  CH 3 OH . We PUT a 1 in front of it to remind ourselves that the number is now fixed. We start with 1 CH 3 OH + O 2 → CO 2 + H 2 O Balance  C : We have  1 C on the left, so we need  1 C on the right. We put a 1 in front of the  CO 2 . 1 CH 3 OH + O 2 → 1 CO 2 + H 2 O Balance  H : We can't balance  O because we have two oxygen-containing MOLECULES without COEFFICIENTS. ∴ Let's balance  H instead. We have  4 H on the left, so we need  4 H on the right. There are already  2 H atoms on the right. We must put a 2 in front of the  H 2 O . 1 CH 3 OH + O 2 → 1 CO 2 + 2 H 2 O Balance  O : We have fixed  4 O on the right and  1 O on the left. We need  3 O on the left. Uh, oh! Fractions! We start over, this time doubling all the coefficients. 2 CH 3 OH + O 2 → 2 CO 2 + 4 H 2 O Now we can balance  O by putting a 3 in front of  O 2 2 CH 3 OH + 3 O 2 → 2 CO 2 + 4 H 2 O Every formula now has a coefficient. We should have a balanced equation.