1.0 Kg of Iron (Fe), having atomic mass equal to 56 g mol–1 contains

1.	1.0 Kg of Iron (Fe), having atomic mass equal to 56 g mol–1 contains (1) 2.88 x 1024 atoms (2) 6.93 x 1023 atoms (3) 6.93 x 1021 atoms (4) 1.075 x 1025 atoms
Answer» (4) 1.075 x 10²⁵ atoms No. of moles = 1000g / 56g = 17.8 moles. 1 mole contains N_A atom of Fe So, 17.8 mole contain 17.8 x 6.022 x 10²³ = 1.075 x 10²⁵ atoms

1.0 Kg of Iron (Fe), having atomic mass equal to 56 g mol–1 contains (1) 2.88 x 1024 atoms (2) 6.93 x 1023 atoms (3) 6.93 x 1021 atoms (4) 1.075 x 1025 atoms

Answer»

(4) 1.075 x 10²⁵ atoms

No. of moles = 1000g / 56g = 17.8 moles.

1 mole contains N_A atom of Fe

So, 17.8 mole contain

17.8 x 6.022 x 10²³ = 1.075 x 10²⁵ atoms

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1.0 Kg of Iron (Fe), having atomic mass equal to 56 g mol–1 contains (1) 2.88 x 1024 atoms (2) 6.93 x 1023 atoms (3) 6.93 x 1021 atoms (4) 1.075 x 1025 atoms

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