1 10-4 mho cm98. 0.04 N solution of a weak acid has specific corductance 4.23 xand degree of dissociation is 0.0612. Theequivalent conductance (Ohm em equiv l) of weak acid atinfinite dilution is solve

1 10-4 mho cm98. 0.04 N solution of a weak acid has specific corduct

1.	1 10-4 mho cm98. 0.04 N solution of a weak acid has specific corductance 4.23 xand degree of dissociation is 0.0612. Theequivalent conductance (Ohm em equiv l) of weak acid atinfinite dilution is solve
Answer» .04 N solution of a weak acid has specific conductance 4.23 × 10−4 MHO cm−1 and degree of dissociation is 0.0612. To find:The equivalent conductance (Ohm em equiv L) of weak acid at INFINITE dilution.Solution:From the given information, we have the data as follows.0.04 N solution of a weak acid has specific conductance 4.23 × 10−4 mho cm−1 and degree of dissociation is 0.0612. A = k × 1000/NA = 4.23 × 10^-4 × 1000/0.04A = 10.575α = A/A∞⇒ A∞ = A/αA∞ = 10.575/0.0612∴ A∞ = 172.79Therefore, the equivalent conductivity at infinite dilution is 172.79