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1.5 g of hydrocarbon on combustion in excess of oxygen produces 4.4 g of `CO_(2)` and 2.7 g of `H_(2)O`, the data illustratesA. Law of conservation of massB. Law of multiple proportionsC. Law of constant compositionD. Law of reciprocal proportions. |
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Answer» Correct Answer - A Mass of hydrocarbon CH = 1.5 g changes to `CO_(2)` and H changes to `H_(2)O` C in `4*4` g of `CO_(2) = 1*2g` H in `2*7 g` of `H_(2)O = (2xx2*7)/(18) = 0*3g` Mass of C + Mass of H `= 1*2 + 0*3 = 1*5g` Which is equal to the mass of hydrocarbon taken. |
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