1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is

1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide.

1.	1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is
Answer» <html><body><p>`1.520`<br/>0.995<br/>`19.00`<br/>`9.00`</p>Solution :`("wt. of <a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> <a href="https://interviewquestions.tuteehub.com/tag/hydroxide-493242" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROXIDE">HYDROXIDE</a>")/("wt. of metal <a href="https://interviewquestions.tuteehub.com/tag/oxide-1144484" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDE">OXIDE</a>") = (<a href="https://interviewquestions.tuteehub.com/tag/em-969731" style="font-weight:bold;" target="_blank" title="Click to know more about EM">EM</a>+ EOH^(-))/(EM + <a href="https://interviewquestions.tuteehub.com/tag/eo-452332" style="font-weight:bold;" target="_blank" title="Click to know more about EO">EO</a>^(-))` <br/> `:.(1.520)/(0.995) = (x+17)/(x+8)` <br/> `:.1.520x+1.520xx8=0.995x+0.995xx17` <br/> `:.1.520x+12.160=0.995x+16.915` <br/> `:.0.525x=4.755` <br/> `:.x=(4.755)/(0.525)= 9.057`</body></html>