1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is

1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide.

1.	1.520 g of the hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is
Answer» `1.520` 0.995 `19.00` `9.00` Solution :`("wt. of METAL HYDROXIDE")/("wt. of metal OXIDE") = (EM+ EOH^(-))/(EM + EO^(-))` `:.(1.520)/(0.995) = (x+17)/(x+8)` `:.1.520x+1.520xx8=0.995x+0.995xx17` `:.1.520x+12.160=0.995x+16.915` `:.0.525x=4.755` `:.x=(4.755)/(0.525)= 9.057`