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1.60 g of a metal were dissolved in HNO_3 to prepare its nitrate. The nitrate was strongly heated when 2.0 g of the metal oxide was obtained. Calculate the equivalent weight of the metal.

Answer» <html><body><p></p>Solution :Mass of the <a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> taken = 1.60 g <br/> Mass of <a href="https://interviewquestions.tuteehub.com/tag/oxide-1144484" style="font-weight:bold;" target="_blank" title="Click to know more about OXIDE">OXIDE</a> formed = 2.0 g <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` Mass of oxygen that combined with 1.60 g of the metal `=2.0- 1.60 = 0.40 g` <br/> `therefore`Equivalent weight of the metal `=("Mass of the metal")/("Mass of oxygen") xx 8 = 1.60/0.40xx 8 = 32`</body></html>


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