1.

1.725 g of a metal carbonate is mixed with 300 mL of N/10HCI. 10 mL of N/2 sodium hydroxide were required to neutralise excess of the acid. Calculate the equivalent mass of the metal carbonate.

Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/69-331759" style="font-weight:bold;" target="_blank" title="Click to know more about 69">69</a></body></html>


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