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1). 792). 433). 454). 49 |
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Answer» If the first term and the common difference of an arithmetic progression are ‘a’ and ‘d’ RESPECTIVELY, then, nth term of AP = a + (n - 1)d Now, 3rd term = a + 2d = 19----(1) Subtracting (1) from (2), ⇒ 5d - 2d = 37 - 19 ⇒ 3d = 18 ⇒ d = 18/3 = 6 Substituting in (1), ⇒ a = 19 - 2(6) = 7 ∴ 13th term of AP = a + 12D = 7 + 12(6) = 7 + 72 = 79 |
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