1.80 g of a metal oxide required 833 mL of hydrogen at NTP to be reduced to its metal. Find the equivalent weights of the oxide and the metal.

1.80 g of a metal oxide required 833 mL of hydrogen at NTP to be reduc

1.	1.80 g of a metal oxide required 833 mL of hydrogen at NTP to be reduced to its metal. Find the equivalent weights of the oxide and the metal.
Answer» SOLUTION :24.2, 16.2