1.80 g of impure sample of oxalate was dissolved in water and the solution made to 250 mL. On titration 20 mL of this solution required 30 mL of M/50 KMnO_4 solution . Calculated the percentage purity of the sample.

1.80 g of impure sample of oxalate was dissolved in water and the solu

1.	1.80 g of impure sample of oxalate was dissolved in water and the solution made to 250 mL. On titration 20 mL of this solution required 30 mL of M/50 KMnO_4 solution . Calculated the percentage purity of the sample.
Answer» <html><body><p></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/balanced-389334" style="font-weight:bold;" target="_blank" title="Click to know more about BALANCED">BALANCED</a> chemical equation is : <br/> `2MnO_4^(-)+5C_2O_4^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>-)+16H^(+)rarr2Mn^(2+)+10CO_2+8H_2O`<br/> Applying morality equation , <br/> `((M_1V_1)/n_1)_(KMnO_4)-=((M_2V_2)/n_1)_(C_2O_4^(2-))`<br/> `1/50xx30/2-=(M_2xx20)/5` <br/> `M_2=(30xx5)/(50xx2xx20)=0.075M`<br/> <a href="https://interviewquestions.tuteehub.com/tag/molecular-562994" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULAR">MOLECULAR</a> wt. of `C_2O_4^(2-) =88` <br/> Wt of `C_2O_4^(2-) = 0.075 xx88=6.6g` <br/> <a href="https://interviewquestions.tuteehub.com/tag/amount-374803" style="font-weight:bold;" target="_blank" title="Click to know more about AMOUNT">AMOUNT</a> of `C_2O_4^(2-) ` in 250 mL `=(6.6)/1000xx250=1.65g` <br/> % Purity `=(1.65)/(1.80)xx100=91.7%`</body></html>