1.

( 1 + \frac { 3 } { 1 } ) ( 1 + \frac { 5 } { 4 } ) ( 1 + \frac { 7 } { 9 } ) \dots ( 1 + \frac { ( 2 n + 1 ) } { n ^ { 2 } } ) = ( n + 1 ) ^ { 2 }

Answer»

The terms written are (1+3/1)(1+5/4)(1+7/9) = (4/1)(9/4)(16/9)....and so on

here the denominator will cancelled , its precedding numerator, like 4 will be cancelled by !(9/4 ) similarly 9 will be cancelled by 16/9 ...and so on

And the final term left will be (n²+2n+1)/1 =(n+1)²



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