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1 g of water at 100^(@)C is converted into steam at the same temperature. If the volume of steam is 1671 cc find the change in internal energy of the system. Latent heat of steam =2256 J g ^(-1).

Answer» <html><body><p></p>Solution :According to first law of thermodynamics <br/> `dQ = dU + PdV` <br/> `mL = dU + P( <a href="https://interviewquestions.tuteehub.com/tag/vs-724135" style="font-weight:bold;" target="_blank" title="Click to know more about VS">VS</a> - Vw)` <br/> Mass of water `= m = 1 g = 10 ^(-3) kg ` <br/> Latent heat of <a href="https://interviewquestions.tuteehub.com/tag/steam-1226863" style="font-weight:bold;" target="_blank" title="Click to know more about STEAM">STEAM</a> `= L = <a href="https://interviewquestions.tuteehub.com/tag/2256-1824965" style="font-weight:bold;" target="_blank" title="Click to know more about 2256">2256</a> Jg ^(-1) = 2256 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10 ^(3) Jkg ^(-1)` <br/> Changle in internal energy ` = dU = ?` <br/> Atmospheric pressure ` = P = 1. 013 xx 10^(5) Nm ^(-2)` <br/> Volume of steam `V_(s) = 1671 c c = 1671 xx 10 ^(-6) m ^(3)` <br/> Volume fo water `V_(w) = ( "mass")/("density") = (10 ^(-3))/( 10 ^(3)) = 10 ^(-6) m ^(3)` <br/> `dU = mL - P (Vs - vW)` <br/> `= 10^(-3) xx 2256 xx 10 ^(3) - 1. 013 xx 10 ^(5) (1617 xx 10 ^(-5) - 10 ^(-6))` <br/> `= 1156 - 1.013 xx 10 ^(5) xx 10 ^(-6) xx 1670` <br/> `= 2256 - 169.171 = 2086 . 829 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`</body></html>


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