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1). Quantity 1 > Quantity 2 2). Quantity 1 ≥ Quantity 2 3). Quantity 2 > Quantity I4). Quantity 2 ≥ Quantity I

Answer»

Quantity 1:

LET the number be 10x + y and when you reversed the DIGIT, number becomes 10y + x.

Given: When you reverse the digits of a number, the number increases by 27

⇒ (10y + x) - (10x + y) = 27

⇒ (10y + x) - 10x - y = 27

⇒ 9y - 9x = 27

⇒ 9(y - x) = 27

⇒ y - x = 3

⇒ All the possible combination of y and x are = (1, 4), (2, 5), (3, 6), (4, 7), (5, 8), (6, 9)

⇒ Possible numbers other than 14 are = 25, 36, 47, 58 and 69

∴ Quantity 1 = 5

Quantity 2:

Let the number is 10x + y and when you reversed the digit number becomes 10y + x

Given: When you reverse the digits of the number the number increases by 18

⇒ (10y + x) - (10x + y) = 18

⇒ (10y + x) - 10x - y = 18

⇒ 9y - 9x = 18

⇒ 9(y - x) = 18

⇒ y - x = 2

All the possible combination of y and x are = (1, 3), (2, 4), (3, 5), (4, 6), (5, 7), (6, 8) and (7, 9).

Possible numbers other than 13 are = 24, 35, 46, 57, 68 and 79.

∴ Quantity 2 = 6

∴ We can see here that Quantity 2 > Quantity 1



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