1). Rs. 22002). Rs. 240003). Rs. 20004). Rs. 1600

1.	1). Rs. 22002). Rs. 240003). Rs. 20004). Rs. 1600
Answer» FORMULAS to be used:- SI, I = ( P × r × t ) / 100 For CI: $(A\; = \;P\;{\LEFT( {\;1\; + \frac{r}{{100}}\;} \right)^t})$; CI = A – P Where SI is Simple interest, A is the amount at the end of time t, P is the principal, t is time, r is rate Given, CI on a certain sum for 2 years at 6% PER annum. $(A = P{\left( {\;1 + \frac{6}{{100}}} \right)^2})$ ⇒ A = P(1.06)² ⇒ A = 1.1236P ∴ CI = A – P ⇒ CI = 1.1236P – P ⇒ CI = 0.1236P SI on Rs. 412 for 10 years at 6% per annum $(\Rightarrow SI = \frac{{412 \times 10 \times 6}}{{100}})$ ⇒ SI = Rs. 247.20 Given, C.I. of 2 yrs be the same as the S.I. on Rs. 412 for 10 yrs ∴ 0.1236P = 247.20 ⇒ P = Rs. 2000

Answer»

FORMULAS to be used:-

SI, I = ( P × r × t ) / 100

For CI:

$(A\; = \;P\;{\LEFT( {\;1\; + \frac{r}{{100}}\;} \right)^t})$; CI = A – P

Where SI is Simple interest,

A is the amount at the end of time t,

P is the principal,

t is time,

r is rate

Given, CI on a certain sum for 2 years at 6% PER annum.

$(A = P{\left( {\;1 + \frac{6}{{100}}} \right)^2})$

⇒ A = P(1.06)²

⇒ A = 1.1236P

∴ CI = A – P

⇒ CI = 1.1236P – P

⇒ CI = 0.1236P

SI on Rs. 412 for 10 years at 6% per annum

$(\Rightarrow SI = \frac{{412 \times 10 \times 6}}{{100}})$

⇒ SI = Rs. 247.20

Given, C.I. of 2 yrs be the same as the S.I. on Rs. 412 for 10 yrs

∴ 0.1236P = 247.20

⇒ P = Rs. 2000

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