1 Sides of a triangular field ar 15m, 16m and 17m. With the three cormersof the field a cow, a buffalo and a horse are tied separately with ropes oflength 7m each to graze in the field. Find the area of the field, whichcannot be grazed by the three animals?

1 Sides of a triangular field ar 15m, 16m and 17m. With the three corm

1.	1 Sides of a triangular field ar 15m, 16m and 17m. With the three cormersof the field a cow, a buffalo and a horse are tied separately with ropes oflength 7m each to graze in the field. Find the area of the field, whichcannot be grazed by the three animals?
Answer» Let ABC be the triangular field with sides Ac = 15 m, AB = 16 m and BC = 17 mAnd,Let the place where the cow, the buffalo and thehorse are tied, are three sectors i.e. sector ADE, sector BFG and sector CHIThe area of triangular field by Heron's formula =√s(s-a)(s-b)(s-c)s = (a+b+c)/2s = (15+16+17)/2s = 48/2s = 24 m√24(24-15)(24-16)(24-17)√24987√12096Area of triangular field = 109.98 sq mArea of the grazed part = Area of the triangular field = Area of the sector ADE + Area of sector BFG + Area of sector CHI= π7²∠A/360 + π7²∠B/360 +π7²∠C/360=π7²(∠ A + ∠ B + ∠ C)/360= 22/777*180/360= 154/2Area of the grazed part = 77 sq mNow, the area of the field which cannot be grazed by these animals= 109.98 - 77= 32.98 sq m