1. The following table shows the ages ofthe patients admitted in a hos

1.	1. The following table shows the ages ofthe patients admitted in a hospital during a years in yeun5-15 15-3 215 359 235-46 65-5 5-465-15 15-25 25-35 35-45 45-5555-65Numberof patients6212314Find the mo de and the mean ofthe data given above. Compare and interpret the twomeasures of cen tral tendencyl lifitime fin hours) of 225
Answer» Step-by-step explanation: Given , data about a total of 200 patients in different age groups ho have visited the hospital. If we summarize the given data in the table, along side Less than cumulative frequency C.I. No of patients less than cf 10-20 40 40 20-30 32 72 30-40 35 107 40-50 45 152 50-60 33 185 60-70 15 200 Clearly, 100th patient all in the 30-40 Age group, SO if we consider 30-40 as out median class, From the formula of median , M = L + (N/2 - C)w/f where L = lower boundary of the median class = 30 N = total frequency = 200 C = cumulative frequency of the class preceding the median class = 72 f = frequency of the median class = 35 w = width of the median class i.e. upper boundary - lower boundary = 10 Thus, Median = 30 + (200/2 - 72)10/35 = 30 + 28*10/35 = 30 + 8 = 38. Hence, Median of the ages of the patients = 38. please hit like if you find it useful

1. The following table shows the ages ofthe patients admitted in a hospital during a years in yeun5-15 15-3 215 359 235-46 65-5 5-465-15 15-25 25-35 35-45 45-5555-65Numberof patients6212314Find the mo de and the mean ofthe data given above. Compare and interpret the twomeasures of cen tral tendencyl lifitime fin hours) of 225

Answer»

Step-by-step explanation:

Given , data about a total of 200 patients in different age groups ho have

visited the hospital.

If we summarize the given data in the table, along side Less than cumulative frequency C.I. No of patients less than cf 10-20 40 40

20-30 32 72

30-40 35 107

40-50 45 152

50-60 33 185

60-70 15 200

Clearly, 100th patient all in the 30-40 Age group,

SO if we consider 30-40 as out median class,

From the formula of median , M = L + (N/2 - C)*w/f where

L = lower boundary of the median class = 30

N = total frequency = 200

C = cumulative frequency of the class preceding the median class = 72

f = frequency of the median class = 35

w = width of the median class i.e. upper boundary - lower boundary = 10

Thus, Median = 30 + (200/2 - 72)*10/35

= 30 + 28*10/35

= 30 + 8

= 38.

Hence, Median of the ages of the patients = 38.

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