1) Total number of electron paire= (1)/(2) (number of valence electrons pm electron (for ionic charge) 2) Number of bond electron pairs= number of atoms - 3) Number of electron pairs around central atom= total number of electron pairs - 3 [number atoms (except H)] 4) Number lone pair = (number of central electron pairs - number bond pairs) Read the above method and answer the following questions : Pair of species with same shape and same state of hybridisation of the central atom is :

1) Total number of electron paire= (1)/(2) (number of valence electron

1.	1) Total number of electron paire= (1)/(2) (number of valence electrons pm electron (for ionic charge) 2) Number of bond electron pairs= number of atoms - 3) Number of electron pairs around central atom= total number of electron pairs - 3 [number atoms (except H)] 4) Number lone pair = (number of central electron pairs - number bond pairs) Read the above method and answer the following questions : Pair of species with same shape and same state of hybridisation of the central atom is :
Answer» <html><body><p>`PCI_(<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) , ICI_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)^(-)` <br/>`NH_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>), H_(2)O`<br/>`NH_(3),CIO_(3)^(-)`<br/>`ICI_(4)^(-),CIO_(3)^(-)`</p>Answer :C</body></html>