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10. In Fig. 10.17, XY and X'Y' are two parallel tangents to a circle with centre O and another tangenAB with point of contact C intersecting XY at A and X' Y' at B. Prove that < AOB = 90°0x' |
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Answer» Join OC In Δ OPA and Δ OCA OP = OC (radii of same circle) PA = CA (length of two tangents) AO = AO (Common) Therefore, Δ OPA ≅ Δ OCA (By SSS congruency criterion) Hence, ∠ 1 = ∠ 2 (CPCT) Similarly ∠ 3 = ∠ 4 Now, ∠ PAB + ∠ QBA = 180° 2∠2 + 2∠4 = 180° ∠2 + ∠4 = 90° ∠AOB = 90° (Angle sum property) |
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