1.

10. The population of a place increased to 54,000 in 2003 at a rate of 5% per annum(1) find the population in 2001.(ii) what would be its population in 2005?

Answer»

option I is the correct answer

1) 2003 =5%2002= 5% =10%so population in 2001 54000× 10% = 5400=54000 - 5400 = 48,6002)2004 = 5%2005 = 5% = 10%54,000 × 10% = 5,400so population in 2005 =54,000 + 5,400 = 59,400

the correct answer is 59400 people in 2005

(1) let the population in 2001 = X A/Q,X (1+5/100)^2 = 54000X(21/20)^2 = 54000X = (54000 x 400)/441X = 48979.59 = 48980 (approx) ANS..

(2)population in 2005 = 54000 ( 1 + 5 /100)^2 = (54000 X 441)/400 = 59535. (ANS)

the population in 2001is 52001 and the population in 2005 is 56005

59; 535 is right answer

5400 and 540000 it is answer

The answer is 59400 people

1-2003=5% 2002=5%=10% by this population in 2001 =54,000 - 5,400 = 48,6002-2004 = 5% 2005=10% 54,000×10%=5,400 by this population of 2005=54,000+5,400=59,400this is right answer

let the no be x the population in 2001 2003=5/:2002 =5 ==10

49600 in year 200159400 in year 2005

59400 people in 2005

3 ANSWERhusuevvsgzhzhdbdbdjdjdjjd

The population in 2001 is 52001and the population in 2005 is 56005

the population in 2001 is 52001 and the population in 2005 is 56005

1)2003=5%2002=5%=10%so population in 200154000×10%=5400=54000-5400=48,6002)2004=5% 2005=5%=10%54,000×10%=5400so population in 2005=54,000+5,400=59,400

1 answer is 48600 and 2 answer is 59400

1)486002)59400 are the best answers

The 15th Indian Census was conducted in two phases, house listing and .... The population of India as per 2011 census was 1,210,193,422. India added 181.5 ..... See also[edit]. flag...

Total population:1,210,193,422

Most populous state:Uttar Pradesh(199,812,341)

Least populous state:Sikkim(610,577)

Date taken:2010–2011

2003=5%2002=5%=10%so population in 200154000×10%=5400=54000-5400=48,6002)2004=5%2005=5%=10%54000×10%=5,400so population in 2005=54,000+5,400=59,400.plz mark me best answer and like my answer.

1)2003=5%2002=5%=10%so population in 200154000×10%=5400there for 54000-5400 =48,600 2)2004=5%2002=5%=10%54,000×10%=5,400so the population in 2005=54,000+5,400=59,400 is the answer

2003=5%2002=5%=10%so population in 200154000 × 10%=5400=48,600) I

I) a = p - I I = 54000*2*5/100 = 5400a = 54000-5400 = 48600ii) a = p + I I = 54000*2*5/100= 5400a = 54000 + 5400= 59400

1 Solution:-

2003=5%2002=5%=10%So Population In 200154000×10%=5400=54000-5400=48600

2 Solution:-

2004=5%2005=5%=10%54000×10%=5400So Population In 2005=54000+5400=59400

is the best answer

1) 2003 = 5℅. 2002= 5℅. so population in 2001. 54000×10℅=5400. =54000-5400=48,600. 2).2004 =5℅. 2005=5℅=10℅. so population in 2005. =54000+5,400= 59,400

first answer is48600 and second answer is 59400

1)2003=5 percentage 2002=5 percentage=10 percentage54000 into 10 percentage is equals to 5400is equals to 54000 - 5400 is equals to 4860second problem2004 =25 percentage2005 is equals to 5% is equals to 10 percentage54000 + 5400 is equals to 59400

I also don't Mysore sandal

answers 1. 48,600. 2. 59,400

48600 in 2001 population and 5940 in 2005

59400 is the right answer of the following

59400. people in 2005is the best answer

¡ ) 2003 = 5% 2002 = 5% = 10% So" population in 2001 54000 × 10% = 5400 =54000 - 5400 = 48,600 ;¡¡ ) 2004 = 5% 2005 = 5% = 10% 54,000 × 10% = 5,400So" population in 2005 = 54,000 + 5,400 = 59,400 ;

《~Now everything is clear~》

59400 is the best answer

59400 is the best answer

59400. is your answer

59400 people in 2005

59400 is the best a swer

a) 2003=5%2002=5%=10%So, population in 200154000×10%=5400=54000-5400=48600b) 2004=5% 2005=5%=10% 54000×10%=5400So, population in 2005=54000+5400=59400

48600 and 59400 is the best answer

option 2 is correct answer

population in 2003 =54,000increasing rate 5% per annum =(54000×5/100)=540×5=2700 2700 for 1 year (per annum)so for (2003-2001) or (2005-2003)=2 years =2700×2=5400

(i) population in 2001=(54000-5400)=48600 ✔(ii) population in 2005=(54000+5400)=59,400✔

59400 is right answer

1)population in 2003 = 5%population in 2002=

(d) is right Best andwer

Given:

we use formula of amount of compound interest to find population

A( 2003)= 54,000,

R = 5%,

n= 2 years

In 2001 Population would be less than 2003 in two years.

A(2003)= P(2001)(1+R/100)^n

54000 = P (2001)(1+5/100)²

54000 = P(2001)(1+1/20)²

54000= P(2001)(21/20)²

54000 = P(2001)((21×21)/(20×20))

P(2001)=( 54000×20×20)/21×21

Population in 2001 = 48979.59= 48980(approx)

(ii)ATQ, population is increasing. Therefore population in 2005,

A(2005)= P(1+R/100)^n

= 54000(1+5/100)²

= 54000(1+1/20)²

= 54000( 21/20)²

= 54000(21/20)× (21/20)

=( 54000× 441)/ 400

=( 540×441)/4

= 238140/4

= 59535

Population in 2005=59535

==========================================================Hope this will help you....

plz like my answer and accept as best

1)48,600="population in 2001"2)59,400="population in 2005"

Population in 2001=48,600Population in 2005=59,400

population in 2001 is 48600

in 2005 answer is 59400

2003=5% population increase in 2002 and. 2003 is =10%so in 2001 = 54000 x 10%= 5400and in 2005 =10%=5400=54000 +5400=59400



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