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1000 drops of a liquid each of diameter 4 mm coasesce to form a single large drop. If surface tension of liquid is 35 dyne cm^(-1). Calculate the energy evolvedby the system in the process. |
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Answer» SOLUTION :NUMBER of drops ` n =1000 impliesn^(1//3)=10impliesn^(2//3)=100` SURFACE tension of liquid `S=35"dyne"cm^(-1)` RADIUS of each small drop `r=2mm=0.2cm` ENERGY evolved in merging `W=4pir^(2)S[n-n^(2//3)]` `impliesW=4xx22/7xx(2xx10^(-1))^(2)35[1000-100]` `impliesW=(88xx35xx4xx10^(-2))/6[900]` `=15840` ergs `~~1.58xx10^(-3)J` |
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