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10ml of a gaseous hydrocarbon on combustion gives 40ml of CO_(2) and 50ml of H_(2)O vapour under the same conditions. The hydrocarbon is |
Answer» <html><body><p>`C_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)H_(6)`<br/>`C_(6)H_(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)`<br/>`C_(4)H_(8)`<br/>`C_(4)H_(10)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`C_(x)H_(y)rarrxCO_(2)+(y)/(2)H_(2)O` <br/> `10rarr40rarr50` <br/> `impliesx=4impliesy=10`</body></html> | |