11.2 g carbon reacts completely with 19.63 litre `O_(2)` at NTP. The cooled gases are pased through 2 litre of 2.5 N NaOH solution. Calculate concentration of remaining NaOH and `Na_(2)CO_(3)` in solution. (CO does not react with NaOH under these conditions.)

11.2 g carbon reacts completely with 19.63 litre `O_(2)` at NTP. The c

1.	11.2 g carbon reacts completely with 19.63 litre `O_(2)` at NTP. The cooled gases are pased through 2 litre of 2.5 N NaOH solution. Calculate concentration of remaining NaOH and `Na_(2)CO_(3)` in solution. (CO does not react with NaOH under these conditions.)
Answer» Let x moles of carbon be converted into CO and y moles of carbon be converted into `CO_(2)`. `underset(x)(C )+(1)/(2)underset(x//2)(O_(2)) to CO` `underset(y)C+underset(y)(O_(2)) to CO_(2)` Total volume of oxygen used `=(x)/(2)xx22.4+yxx22.4` =19.63 11.2x+22.4y=19.63 `x+y=(11.2)/(12)`, i.e., 12x+12y=11.2 Solving eqs. (i) and (ii), we get x=0.11, y=0.82 Number of moles of `CO_(2)` formed =0.82 Number of milliequivalents of NaOH solution through which `CO_(2)` is massed `=NxxV=2.5xx2000=5000` Number of milliequivalents of `CO_(2)` passed`=0.82xx2xx1000` =1640 `2NaOH+CO_(2) to Na_(2)CO_(3)+H_(2)O` Number of milliequivalents of `Na_(2)CO_(3)=1640` `N_(Na_(2)CO_(3))=(1640)/(2000)=0.82` Number of milliequivalents of remaining NaOH =5000-1640=3360 Normality of remaining `NaOH=(3360)/(2000)=1.68`

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11.2 g carbon reacts completely with 19.63 litre `O_(2)` at NTP. The cooled gases are pased through 2 litre of 2.5 N NaOH solution. Calculate concentration of remaining NaOH and `Na_(2)CO_(3)` in solution. (CO does not react with NaOH under these conditions.)

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