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11.2 L of oxygen STP and 8 grams of calcium are allowed to react. What volume of which chemical 3 is left unreacted? |
Answer» <html><body><p></p>Solution :The balanced chemical <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> is <br/> `2Ca+O_(2)to 2CaO` <br/> 2 moles of Ca=1 moles of `O_(2)` <br/> (2 x 40) grams of Ca=22.4 L of `O_(2)` at STP <br/> 8 grams of Ca=2.24 L of `O_(2)` at STP <br/> The limiting <a href="https://interviewquestions.tuteehub.com/tag/reagent-1178480" style="font-weight:bold;" target="_blank" title="Click to know more about REAGENT">REAGENT</a> is calcium. <br/> Volume of `O_(2)` at STP required=2.24 L <br/> Volume of `O_(2)` left unreacted =11.2-2.24 <br/> =8.96 L at STP</body></html> | |