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12.25 g of KClO_3 and 5.85 g of NaCl ar heated together. The residue obtained at the end of burning is dissolved in water to prepare a 500 mL solution. To the solution obtained, excess of AgNO_3 is added. Find the moles of white precipitate formed. Also find the molarity of the solution after filtering out the precipitate with respect to NaNO_3 and KNO_3 (molecular mass of KClO_3 is 122.5 and that of NaCl is 58.50)

Answer» <html><body><p></p>Solution :`12.25 g KClO_3-=0.1 <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>` <br/> `5.85 g NaCl-=0.1 mol` <br/> `2KClO_3overset(Delta)to2KCl+3O_2` <br/> `NaCloverset(Delta)toNaCl` (does not <a href="https://interviewquestions.tuteehub.com/tag/decompose-2048105" style="font-weight:bold;" target="_blank" title="Click to know more about DECOMPOSE">DECOMPOSE</a>) <br/> `{:(KCloverset(AgNO_3)toAgCl+KNO_3),(NaClunderset(AgNO_3)toAgCl+NaNO_2):}` <br/> `implies` <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> of `<a href="https://interviewquestions.tuteehub.com/tag/agcl-368919" style="font-weight:bold;" target="_blank" title="Click to know more about AGCL">AGCL</a>=(0.1)+(0.1)=0.2` <br/> Moles of `KNO_3=0.1` <br/> `M=0.2` M <br/> <a href="https://interviewquestions.tuteehub.com/tag/similarly-1208242" style="font-weight:bold;" target="_blank" title="Click to know more about SIMILARLY">SIMILARLY</a>, `M_(NaNO_3)=0.2M`</body></html>


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