13. H+(aq) + oh- (aq) = h2o(l) H = - 57kj/mol Nh4oh(aq) = nh4+ + oh- – InterviewSolution

1.	13. H+(aq) + oh- (aq) = h2o(l) H = - 57kj/mol Nh4oh(aq) = nh4+ + oh- H = +5 kj/mol Calculate the value of heat of neutralization of NH4OH solution with strong acid, when it is 20% ionised. A. -52kj/mol B. -51kj/mol C. -53kj/mol D. -57kj/mol
Answer» 13. H+(aq) + oh- (aq) = h2o(l) H = - 57kj/mol Nh4oh(aq) = nh4+ + oh- H = +5 kj/mol Calculate the value of heat of neutralization of NH4OH solution with strong acid, when it is 20% ionised. A. -52kj/mol B. -51kj/mol C. -53kj/mol D. -57kj/mol

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