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`13g` of metal `M` is deposited at cathode by passing `0.4F` of electricity . The cathodic reaction is `:` `M^(n+)+n e^(-) rarr M` The formula of metal chloride `(Aw=65)` is `……………………..` . |
Answer» Correct Answer - `(MCl_(2))` `(MCl_(2))` `0.4F=0.4Eq of M=(13.0g)/(Ew)` `:. Ew=32.5` Valency `=(Aw)/(Ew)=(65)/(32.5)=2` Formula `=MCl_(2)` |
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