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15.0g of an unknown molecular material is dissolved in 450g of water. The resulting solution freezes at -0.34^(@)C. What is the molar mass of the material? K_(f) for water = 1.86K kg mol^(-1). |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`W_(("<a href="https://interviewquestions.tuteehub.com/tag/solvent-1217160" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVENT">SOLVENT</a>"))=15.0g` <br/>` W_(("solvent")) =450g` <br/> `Delta T_(f) = T_(1) ^(0) - T_(f) =0-(-0.34)=0.34^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>` <br/> `Delta T_(f)= k _(f) m` <br/> `0.34 =1.86 xx (15)/(M) xx (1000)/(450)` <br/> `M = (1.86 xx 15 xx 1000)/(0.34 xx 450) = 182. <a href="https://interviewquestions.tuteehub.com/tag/35-308504" style="font-weight:bold;" target="_blank" title="Click to know more about 35">35</a> g <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>^(-1).`</body></html> | |