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(16) A fluoride disposal plant was constructed to carry out the following reactions F2 + 2NaOH → ½ O2 + 2NaF + H2O2NaF + CaO + H2O → CaF2 + 2NaOHAs the plant operated, enough lime was added from time to time to just bring out the complete precipitation of fluorine as CaF2. Over a period of time 2000 kg of fluorine was fed into the plant and 6000 kg of lime was added. What was the percentage utilization of lime?​

Answer»

(0028)No of moles of LIME required = 5610000×10 3 (m) out of CaO=56=1.286×10 5 No. of moles of F 2 fed = 191900×10 3 =105 moles2F 2 +4 NaOH→4NaF+2H 2 O+O 2 −−−(1)According to given reaction, moles FORMED of NaF only its half used in second reaction of below 2NaF+CaO+H 2 O→CaF 2 +NaOH22×10 5 =10521 ×10 5 =0.5×10 5 % utilisation of lime = no. of mole of lime requiredNo of mole of lime UTILISED = 1.786×10 5 0.5×10 5 ×100=28%answer =(0.028)



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