16 g of an ideal gas SO_(X) occupies 5.6 L at S.T.P. What is its molecular mass ? What is the value of X ?

16 g of an ideal gas SO_(X) occupies 5.6 L at S.T.P. What is its molec

1.	16 g of an ideal gas SO_(X) occupies 5.6 L at S.T.P. What is its molecular mass ? What is the value of X ?
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :5.6 <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> of the <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> at S.T.P weigh = 16 g <br/> 22.4 L of the gas at S.T.P. weigh `= ((1.6g))/((5.6L))xx(22.4L)=<a href="https://interviewquestions.tuteehub.com/tag/64g-1909876" style="font-weight:bold;" target="_blank" title="Click to know more about 64G">64G</a>` <br/> By definition, molar mass of gas `(SO_(X))=64g` <br/> `:. 32+x(16)=64or16x=64-32=32orx=2` <br/> Value of x = 2 and the gas `= SO_(2)`</body></html>