16 g of oxygen has same number of molecules as in

1.	16 g of oxygen has same number of molecules as in
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/16-276476" style="font-weight:bold;" target="_blank" title="Click to know more about 16">16</a> g of CO<br/>28 g of `N_(2)`<br/>14 g of `N_(2)`<br/>1.0 g of `H_(2)`</p>Solution :The calculation of molecule can be done as follows : <br/> <a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of molecules `= ("Mass")/("Molar mass") <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> "Avogadro"` <br/> No. of molecules , in 16 g oxygen `=(16)/(32) xx N_(A)=(N_(A))/(3)` <br/> In 16 g of `CO=(16)/(32)xxN_(A)=(N_(A))/(1.75)` <br/> In 28 g of `N_(2) = (28)/(28) xx N_(A)=N_(A)` <br/> In 14 g of `N_(2) = (14)/(28)xx N_(A) = (N_(A))/(2)` <br/> In 1 g of `H_(2)=(1)/(2) xx N_(A) = (N_(A))/(2)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, 16 g of `O_(2)= 14 g` of `N_(2) = 1.0 g ` of `H_(2)`</body></html>

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