18.0 g of water completely vaporises at 100^(@)C and 1 bar pressure and the enthalpy change in the process is40.79 kJ mol^(-1). What will be the enthalpychange for vaporising two moles of water under the same conditions ? What is the standard enthalpy of vaporisation for water ?

18.0 g of water completely vaporises at 100^(@)C and 1 bar pressure an

1.	18.0 g of water completely vaporises at 100^(@)C and 1 bar pressure and the enthalpy change in the process is40.79 kJ mol^(-1). What will be the enthalpychange for vaporising two moles of water under the same conditions ? What is the standard enthalpy of vaporisation for water ?
Answer» <html><body><p></p>Solution :`18.0` g of <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> `=` 1 mole<br/> `:. ` Standard <a href="https://interviewquestions.tuteehub.com/tag/enthalpy-15226" style="font-weight:bold;" target="_blank" title="Click to know more about ENTHALPY">ENTHALPY</a> of vaporisation at`100^(@)<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>` and 1 bar pressure `=40.79 kJ <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>^(-1)`<br/> Enthalpy change in vaporisationof 2 moles of water `= 2 xx 40.79 kJ = 81. 58 kJ`</body></html>