1.

18.0 g of water completely vapourises at 100^(@)C and 1 bar pressure and the enthalpy change for the process is 40.79 kJ mol^(-1). (i) What will be the enthalpy change for vapourising 2 moles of water under the same conditions? (ii) What is the standard enthalpy of vapourisation for water?

Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :18.0 of water = 1 <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a> <br/> Standard enthalpy of <a href="https://interviewquestions.tuteehub.com/tag/vaporisation-1442866" style="font-weight:bold;" target="_blank" title="Click to know more about VAPORISATION">VAPORISATION</a> at `100^(@)C` and 1 bar <a href="https://interviewquestions.tuteehub.com/tag/pressure-1164240" style="font-weight:bold;" target="_blank" title="Click to know more about PRESSURE">PRESSURE</a> = `40.79 kJ"mol"^(-1)`. <br/> Enthalpy change in vaporisation of 2 mol of water `= 2 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 40.79 = 81.58` kJ.</body></html>


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