180 mL of a hydrocarbon diffuse through a porous membrane in 15 minutes, while 120 mL of SO_2 under identical conditions diffuse in 20 minutes. What is the molecular mass of the hydrocarbon ?

180 mL of a hydrocarbon diffuse through a porous membrane in 15 minute

1.	180 mL of a hydrocarbon diffuse through a porous membrane in 15 minutes, while 120 mL of SO_2 under identical conditions diffuse in 20 minutes. What is the molecular mass of the hydrocarbon ?
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Rate of diffusion of hydrocarbon<br/> `(r_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)) = 180//15 = 12` mL/<a href="https://interviewquestions.tuteehub.com/tag/min-548008" style="font-weight:bold;" target="_blank" title="Click to know more about MIN">MIN</a> <br/> Rate of diffusion of `SO_(2)(r_(2)) = 120/20 = 6 mL`/min <br/> Molecular mass of `SO_(2) (M_(2)) = <a href="https://interviewquestions.tuteehub.com/tag/32-307188" style="font-weight:bold;" target="_blank" title="Click to know more about 32">32</a> + (2 xx 16) = 64` <br/> According to Graham.s <a href="https://interviewquestions.tuteehub.com/tag/law-184" style="font-weight:bold;" target="_blank" title="Click to know more about LAW">LAW</a> of diffusion, `r_(1)/r_(2) = sqrt(M_(2)/M_(1))` <br/>Substituting the values, we get `12/6 = sqrt(64/M_(1))` <br/> or `M_(1) = (6 xx 6 xx 64)/(12 xx 12) = 16` <br/> Hence, the molecular mass of the hydrocarbon is 16.</body></html>