19.5 g of benzene on burning in the free supply of oxygen liberated 12.6 kJ of energy at constant pressure. Calculate the enthalpy of combustion of benzene. Write the thermochemical equation.

19.5 g of benzene on burning in the free supply of oxygen liberated 12

1.	19.5 g of benzene on burning in the free supply of oxygen liberated 12.6 kJ of energy at constant pressure. Calculate the enthalpy of combustion of benzene. Write the thermochemical equation.
Answer» <html><body><p></p>Solution :19.5 <a href="https://interviewquestions.tuteehub.com/tag/grams-476111" style="font-weight:bold;" target="_blank" title="Click to know more about GRAMS">GRAMS</a> of benzene on burning liberated 126 kl. 78 grams of benzene on burning liberated 502 <a href="https://interviewquestions.tuteehub.com/tag/kj-1063034" style="font-weight:bold;" target="_blank" title="Click to know more about KJ">KJ</a>. <br/> The <a href="https://interviewquestions.tuteehub.com/tag/enthalpy-15226" style="font-weight:bold;" target="_blank" title="Click to know more about ENTHALPY">ENTHALPY</a> of combustion of benzene is` -502 kJmol ^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>).`The thermochemical equation is given as, <br/> `C _(<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>) H _(6(l)) + (15)/(2) O _(2(g)) to 6CO _(2(g)) + 3H_(2(g)) + 3H _(2) O _((l)), Delta H =-502 kJ mol ^(-1)`</body></html>