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2.3 gm Na is added to 6 gm of `CH_(3)CO OH`. The volume of `H_(2)` gas liberated at S.T.P.A. 1.12 LB. 2.24LC. 3.36 LD. 4.48 L |
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Answer» Correct Answer - 1 `CH_(3)CO OH+Nato CH_(3)CO Ona+1/2 H_(2)` `{:("1 mole","1mole","1/2 mole"),(60 g,23 g,11.2 lit),("0.1 mole","0.1 mole",=?),(=6g,2.3 g,1.12 lit):}` |
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