2.48 g of hydrated sodium thiosulphate (Na_2S_2O_3 .xH_2O) was dissolved per litre of the solution. 25 mL of this solution required 12.5 mL of M /100 iodine solution . Determine the value of x.

2.48 g of hydrated sodium thiosulphate (Na_2S_2O_3 .xH_2O) was dissolv

1.	2.48 g of hydrated sodium thiosulphate (Na_2S_2O_3 .xH_2O) was dissolved per litre of the solution. 25 mL of this solution required 12.5 mL of M /100 iodine solution . Determine the value of x.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The balanced chemical equation is : <br/> `2Na_2S_2O_3+I_2 rarr Na_2S_4O_6+2NaI` <br/> Let the <a href="https://interviewquestions.tuteehub.com/tag/morality-1101596" style="font-weight:bold;" target="_blank" title="Click to know more about MORALITY">MORALITY</a> of `Na_2S_2O_3.xH_2O` be `M_1` <br/> Applying morality equation <br/> `((M_1V_1)/n_1)_(Na_2S_2O_3)=((M_2V_2)/n_2)_(I_2)` <br/> `(M_1xx25)/2-=1/100xx(12.5)/1` <br/> `M_1=(12.5xx2)/(100xx25)=0.01M`<br/> Molecular <a href="https://interviewquestions.tuteehub.com/tag/wt-1462289" style="font-weight:bold;" target="_blank" title="Click to know more about WT">WT</a>. of `Na_2S_2O_3.xH_2O` <br/> `=2xx23+2xx32+3xx16+xxx18` <br/> Amount of `Na_2S_2O_3.xH_2O=0.01xx(158+18x)g` <br/> But actural amount = 2.48 g <br/> `:.0.01(158+18x)=2.48` <br/> `(158+18x)=(2.48)/(0.01)=248` <br/> `18x=248-158=<a href="https://interviewquestions.tuteehub.com/tag/90-341351" style="font-weight:bold;" target="_blank" title="Click to know more about 90">90</a>` <br/> `:. x = 90 / 18 =5`.</body></html>