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2.82 g of glucose is dissolved in 30 g of water. Calculate the mole fraction of glucose and water. |
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Answer» Solution :MASS of glucose `= 2. 82 G` No. of moles of glucose `= (2. 82)/( 180) = (30)/(18) = 1. 67` ` X _(H _(2)O)= (1. 67)/( 1. 67 + 0.016) = (1. 67)/( 1. 686) =0.99` `THEREFORE x _(H _(2)O) + x _("glucose") =1` ` 0.99 + x _("glucose")=1` `x _("glucose")=1-0.99 =0.01` |
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