1.

2.82 g of glucose is dissolved in 30 g of water. Calculate the mole fraction of glucose and water.

Answer»

Solution :MASS of glucose `= 2. 82 G`
No. of moles of glucose `= (2. 82)/( 180) = (30)/(18) = 1. 67`
` X _(H _(2)O)= (1. 67)/( 1. 67 + 0.016) = (1. 67)/( 1. 686) =0.99`
`THEREFORE x _(H _(2)O) + x _("glucose") =1`
` 0.99 + x _("glucose")=1`
`x _("glucose")=1-0.99 =0.01`


Discussion

No Comment Found