2.9 g of a gas at 95^@C occupied the same volume as 0.184 g of dihydrogen at 17^@C, at the same pressure. What is the molar mass of the gas?

2.9 g of a gas at 95^@C occupied the same volume as 0.184 g of dihydro

1.	2.9 g of a gas at 95^@C occupied the same volume as 0.184 g of dihydrogen at 17^@C, at the same pressure. What is the molar mass of the gas?
Answer» <html><body><p></p>Solution :Suppose the molar mass of the <a href="https://interviewquestions.tuteehub.com/tag/gas-1003521" style="font-weight:bold;" target="_blank" title="Click to know more about GAS">GAS</a> is M. According to the gas equation , `PV = <a href="https://interviewquestions.tuteehub.com/tag/nrt-1109890" style="font-weight:bold;" target="_blank" title="Click to know more about NRT">NRT</a>`. Since P and V are the same, we have <br/> For the gas : <br/> `PxxV = (2.9)/M xxRxx(273 +95)` ...(i) <br/> For `H_2 : PxxV= (0.184)/2 xx R xx (273+17)` ...(ii)<br/> From <a href="https://interviewquestions.tuteehub.com/tag/equations-452536" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATIONS">EQUATIONS</a> (i) and (ii), we have <br/> `(2.9)/M xx368 = (0.184)/2 xx <a href="https://interviewquestions.tuteehub.com/tag/290-1834725" style="font-weight:bold;" target="_blank" title="Click to know more about 290">290</a>` <br/> or `M = (2.9 xx 368 xx 2)/(0.184xx290)= 40 g <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>(-1)`</body></html>