2.9 g of a gas at 95^@C occupied the same volume as 0.184 g of dihydrogen at 17^@C, at the same pressure. What is the molar mass of the gas?

2.9 g of a gas at 95^@C occupied the same volume as 0.184 g of dihydro

1.	2.9 g of a gas at 95^@C occupied the same volume as 0.184 g of dihydrogen at 17^@C, at the same pressure. What is the molar mass of the gas?
Answer» Solution :Suppose the molar mass of the GAS is M. According to the gas equation , `PV = NRT`. Since P and V are the same, we have For the gas : `PxxV = (2.9)/M xxRxx(273 +95)` ...(i) For `H_2 : PxxV= (0.184)/2 xx R xx (273+17)` ...(ii) From EQUATIONS (i) and (ii), we have `(2.9)/M xx368 = (0.184)/2 xx 290` or `M = (2.9 xx 368 xx 2)/(0.184xx290)= 40 g MOL(-1)`