2.9 g of a gas at 95^(@)C occupied the same volume as 0.184 g of hydrogen at 17^(@)C at the same pressure. What is the molar mass of the gas ?

2.9 g of a gas at 95^(@)C occupied the same volume as 0.184 g of hydro

1.	2.9 g of a gas at 95^(@)C occupied the same volume as 0.184 g of hydrogen at 17^(@)C at the same pressure. What is the molar mass of the gas ?
Answer» Solution :As `"" P_(1)=P_(2)` and `"" V_(1)=V_(2)`, But PV=nRT `:. "" P_(1)V_(1)=P_(2)V_(2)`, i.e., `n_(1)RT_(1)=n_(2)RT_(2)` `:. "" n_(1)T_(1)= n_(2)T_(2) "or" (w_(1))/(M_(1))T_(1)=(w_(2))/(M_(2))T_(2)` i.e, `"" (2.9)/(M_(X))XX(95+273)=(0.184)/(2)xx(17+273)` or `"" M_(X)=(2.9xx368xx2)/(0.184xx290)=40" G mol"^(-1)`