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2 L of hydrogen and 2.5 L of chlorine are allowed react in diffused light. Write the volume composition of the component gases after reaction.

Answer» <html><body><p></p>Solution :Reaction between and chlorine leading to the production of hydrogen chloride is given as <br/> `H_(2)+Cl_(2)rarr2HCl` <br/> `{:("1 vol","1 vol","2 vol","Gay - Lussac.s volumes"),(2,2.5L,0L,"at <a href="https://interviewquestions.tuteehub.com/tag/start-1224710" style="font-weight:bold;" target="_blank" title="Click to know more about START">START</a>"),(0,0.5L,4L,"after the reaction"):}` <br/> The volume of the mixture is <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>. 5L<br/> Volume of unreacted `Cl_(2)=0.5L` <br/> Volume of `HCl` <a href="https://interviewquestions.tuteehub.com/tag/produced-592947" style="font-weight:bold;" target="_blank" title="Click to know more about PRODUCED">PRODUCED</a> = 4 <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a></body></html>


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