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2 litres of nitrogen completely react with 6 litres of hydrogen under suitable conditions to form 4 litres of NH_3. If all the volumes are measured at the same temperature and pressure, show that the data given are in accordance to the Gay Lussac's law of combining volumes. |
Answer» <html><body><p></p>Solution :The reaction mentioned in the question takes place as follows : <br/> `underset("2 litres")((N_(2)(g)) +underset("<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> litres")(3H_(2)(g)) to underset("4 litres")(2NH_(3)(g))` <br/> The volumes of the reacting gases are in the ratio 2 : 6, i.e., 1: 3. The product ammonia is <a href="https://interviewquestions.tuteehub.com/tag/also-373387" style="font-weight:bold;" target="_blank" title="Click to know more about ALSO">ALSO</a> a gas and its <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> also bears a simple whole number ratio with the volumes of reactants. The ratio of the volumes of all reactants and product in this reaction is thus <br/> 1:3:2 <br/> Since, the ratio is a simple whole number ratio, the data are in <a href="https://interviewquestions.tuteehub.com/tag/accordance-846972" style="font-weight:bold;" target="_blank" title="Click to know more about ACCORDANCE">ACCORDANCE</a> to the Gay Lussac.s law of combining volumes.</body></html> | |